$ \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\abs}[2][]{\left\lvert#2\right\rvert_{\text{#1}}} \newcommand{\ket}[1]{\left\lvert#1 \right.\rangle} \newcommand{\bra}[1]{\langle\left. #1\right\rvert} \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\dd}{\text{d}} \newcommand{\dv}[2]{\frac{\dd #1}{\dd #2}} \newcommand{\pdv}[2]{\frac{\partial}{\partial #1}} $
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Let $T:V\to V$ be a linear transformation. A subspace for $T$ is invarient if $Tu\in U$ for all $u\in U$

Concepts

We care about this because given a basis and an invarient linear transformation for the subspace, we can use the transformation to create another basis.

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Let $T:V\to V$ be a linear transformation. A subspace for $T$ is invarient if $Tu\in U$ for all $u\in U$

Concepts

We care about this because given a basis and an invarient linear transformation for the subspace, we can use the transformation to create another basis.

Used In

Coming soon

Hypothesis

Coming soon

Results

Coming soon
FullPage
definition
concepts
used in
hypothesis
results
FullPage
definition
concepts
used in
hypothesis
results
Let $T:V\to V$ be a linear transformation. A subspace for $T$ is invarient if $Tu\in U$ for all $u\in U$

Concepts

We care about this because given a basis and an invarient linear transformation for the subspace, we can use the transformation to create another basis.

Used In

Coming soon

Hypothesis

Coming soon

Results

Coming soon
Let $T:V\to V$ be a linear transformation. A subspace for $T$ is invarient if $Tu\in U$ for all $u\in U$

Concepts

We care about this because given a basis and an invarient linear transformation for the subspace, we can use the transformation to create another basis.

Used In

Coming soon

Hypothesis

Coming soon

Results

Coming soon
FullPage
definition
concepts
used in
hypothesis
results