$ \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\abs}[2][]{\left\lvert#2\right\rvert_{\text{#1}}} \newcommand{\ket}[1]{\left\lvert#1 \right.\rangle} \newcommand{\bra}[1]{\langle\left. #1\right\rvert} \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\dd}{\text{d}} \newcommand{\dv}[2]{\frac{\dd #1}{\dd #2}} \newcommand{\pdv}[2]{\frac{\partial}{\partial #1}} $
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Let $V$ be a finite dimensional vector space, and $T\in\mathcal{L}(V)$ (ie. T:V\to V). Then there exists a monic polynomial $m_T\in\mathbb{F}[t]$ of minimal degree such that $m_T(T)=0$.

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Let $V$ be a finite dimensional vector space, and $T\in\mathcal{L}(V)$ (ie. T:V\to V). Then there exists a monic polynomial $m_T\in\mathbb{F}[t]$ of minimal degree such that $m_T(T)=0$.

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result
concepts
hypothesis
implications
proof
Let $V$ be a finite dimensional vector space, and $T\in\mathcal{L}(V)$ (ie. T:V\to V). Then there exists a monic polynomial $m_T\in\mathbb{F}[t]$ of minimal degree such that $m_T(T)=0$.

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Proof

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Let $V$ be a finite dimensional vector space, and $T\in\mathcal{L}(V)$ (ie. T:V\to V). Then there exists a monic polynomial $m_T\in\mathbb{F}[t]$ of minimal degree such that $m_T(T)=0$.

Concepts

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Hypothesis

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Results

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Proof

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result
concepts
hypothesis
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proof