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Let $T:V\to V$ be a linear transformation. Then a scalar $\lambda\in\mathbb{F}$ is am eigenvalue if there exists some nonzero vector $x\in V$ such that $Tx=\lambda x$, where $x$ is the eigenvector.
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To find the eigenvalues of $T$, let $\lambda$ be a variable and solve for $\text{det}(T-\lambda I)=0$Used In
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Let $T:V\to V$ be a linear transformation. Then a scalar $\lambda\in\mathbb{F}$ is am eigenvalue if there exists some nonzero vector $x\in V$ such that $Tx=\lambda x$, where $x$ is the eigenvector.
Concepts
To find the eigenvalues of $T$, let $\lambda$ be a variable and solve for $\text{det}(T-\lambda I)=0$Used In
Coming soonHypothesis
Coming soonResults
Coming soon
FullPage
definition
concepts
used in
hypothesis
results