$ \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\abs}[2][]{\left\lvert#2\right\rvert_{\text{#1}}} \newcommand{\ket}[1]{\left\lvert#1 \right.\rangle} \newcommand{\bra}[1]{\langle\left. #1\right\rvert} \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\dd}{\text{d}} \newcommand{\dv}[2]{\frac{\dd #1}{\dd #2}} \newcommand{\pdv}[2]{\frac{\partial}{\partial #1}} $
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Let $V$ be a vector space and $B$ a basis for $V$. Say $B=\{x_1, \dots, x_n\}$ and consider $B$ as an ordered set. Since $B$ is a spanning set, then there exists a linearly independent combination of $x_1, \dots, x_n$ such that for any $x\in V$, we have $x=\alpha_1x_1 +\dots + \alpha_nx_n $ for some unique $\alpha_1, \dots, \alpha_n$. Then the vector $$\begin{align*} \begin{bmatrix}\alpha_1 \\ \dots \\ alpha_n\end{bmatrix} = [x]_{\beta} \end{align*}$$ is the coordinate vector of $x$ with respect to $B$.

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Let $V$ be a vector space and $B$ a basis for $V$. Say $B=\{x_1, \dots, x_n\}$ and consider $B$ as an ordered set. Since $B$ is a spanning set, then there exists a linearly independent combination of $x_1, \dots, x_n$ such that for any $x\in V$, we have $x=\alpha_1x_1 +\dots + \alpha_nx_n $ for some unique $\alpha_1, \dots, \alpha_n$. Then the vector $$\begin{align*} \begin{bmatrix}\alpha_1 \\ \dots \\ alpha_n\end{bmatrix} = [x]_{\beta} \end{align*}$$ is the coordinate vector of $x$ with respect to $B$.

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definition
concepts
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FullPage
definition
concepts
used in
hypothesis
results
Let $V$ be a vector space and $B$ a basis for $V$. Say $B=\{x_1, \dots, x_n\}$ and consider $B$ as an ordered set. Since $B$ is a spanning set, then there exists a linearly independent combination of $x_1, \dots, x_n$ such that for any $x\in V$, we have $x=\alpha_1x_1 +\dots + \alpha_nx_n $ for some unique $\alpha_1, \dots, \alpha_n$. Then the vector $$\begin{align*} \begin{bmatrix}\alpha_1 \\ \dots \\ alpha_n\end{bmatrix} = [x]_{\beta} \end{align*}$$ is the coordinate vector of $x$ with respect to $B$.

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Let $V$ be a vector space and $B$ a basis for $V$. Say $B=\{x_1, \dots, x_n\}$ and consider $B$ as an ordered set. Since $B$ is a spanning set, then there exists a linearly independent combination of $x_1, \dots, x_n$ such that for any $x\in V$, we have $x=\alpha_1x_1 +\dots + \alpha_nx_n $ for some unique $\alpha_1, \dots, \alpha_n$. Then the vector $$\begin{align*} \begin{bmatrix}\alpha_1 \\ \dots \\ alpha_n\end{bmatrix} = [x]_{\beta} \end{align*}$$ is the coordinate vector of $x$ with respect to $B$.

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