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\newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\abs}[2][]{\left\lvert#2\right\rvert_{\text{#1}}} \newcommand{\ket}[1]{\left\lvert#1 \right.\rangle} \newcommand{\bra}[1]{\langle\left. #1\right\rvert} \newcommand{\braket}[1]{\langle #1 \rangle} \newcommand{\dd}{\text{d}} \newcommand{\dv}[2]{\frac{\dd #1}{\dd #2}} \newcommand{\pdv}[2]{\frac{\partial}{\partial #1}}
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A linear transformation is determined by how it acts on a basis

Let T:V\to W be a linear transformation, and \{v_i\}_{i\in I} be a basis for V, and let \{w_i\}_{i\in V} be any vectors in W. Then there's an unique linear transformation T such that Tv_1=w_1 for all i.

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Hypothesis

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Proof

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A linear transformation is determined by how it acts on a basis

Let T:V\to W be a linear transformation, and \{v_i\}_{i\in I} be a basis for V, and let \{w_i\}_{i\in V} be any vectors in W. Then there's an unique linear transformation T such that Tv_1=w_1 for all i.

Concepts

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Hypothesis

Coming soon

Results

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Proof

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FullPage
result
concepts
hypothesis
implications
proof
FullPage
result
concepts
hypothesis
implications
proof

A linear transformation is determined by how it acts on a basis

Let T:V\to W be a linear transformation, and \{v_i\}_{i\in I} be a basis for V, and let \{w_i\}_{i\in V} be any vectors in W. Then there's an unique linear transformation T such that Tv_1=w_1 for all i.

Concepts

Coming soon

Hypothesis

Coming soon

Results

Coming soon

Proof

Coming soon

A linear transformation is determined by how it acts on a basis

Let T:V\to W be a linear transformation, and \{v_i\}_{i\in I} be a basis for V, and let \{w_i\}_{i\in V} be any vectors in W. Then there's an unique linear transformation T such that Tv_1=w_1 for all i.

Concepts

Coming soon

Hypothesis

Coming soon

Results

Coming soon

Proof

Coming soon
FullPage
result
concepts
hypothesis
implications
proof